Asked by nitchelence
The first term of a geometric sequence is 125÷4,the last term is 2, and the sum of the associated series is 203÷4. What is the common ratio and how many terms are there in the series?
Answers
Answered by
Steve
note that 2=8/4
(8/4)/(125/4) = (8/125) = (2/5)^3
Looks to me like r = 2/5 and there are 4 terms:
125/4, 25/2, 5, 2
the sum is 203/4
(8/4)/(125/4) = (8/125) = (2/5)^3
Looks to me like r = 2/5 and there are 4 terms:
125/4, 25/2, 5, 2
the sum is 203/4
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