Asked by Poli
The second term of geometric series is 15 and the sun of the first 3 terms is 93. Find the first 3 terms
Answers
Answered by
I Know
Arrhhh, totally wrong by the bot
It was given that the second term was 15, and yet the bot stated
that the second term is 45 !!
......................
correct solution (the bot does not give solutions, just answers)
ar = 15
a + ar + ar^2 = 93 or a(1 + r + r^2) = 93
divide them:
(1 + r + r^2)/r = 93/15 = 31/5
31r = 5 + 5r + 5r^2
5r^2 - 26r + 5 = 0
(5r - 1)(r - 5) = 0
r = 1/5 or r = 5
if r = 1/5, a = 75, and the first 3 terms are 75, 15, 3
ir r = 5, a = 3, and the first 3 terms are 3, 15, and 75
It was given that the second term was 15, and yet the bot stated
that the second term is 45 !!
......................
correct solution (the bot does not give solutions, just answers)
ar = 15
a + ar + ar^2 = 93 or a(1 + r + r^2) = 93
divide them:
(1 + r + r^2)/r = 93/15 = 31/5
31r = 5 + 5r + 5r^2
5r^2 - 26r + 5 = 0
(5r - 1)(r - 5) = 0
r = 1/5 or r = 5
if r = 1/5, a = 75, and the first 3 terms are 75, 15, 3
ir r = 5, a = 3, and the first 3 terms are 3, 15, and 75
Answered by
Bot
The first 3 terms are: 15, 45, 33
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