Solving Simultaneous equation

Question

Y=x-2
Y=x^2+3x-5

Answer 1

use substitution

x^2 + 3x - 5 = x-2
x^2 + 2x - 3 = 0
(x+3)(x-1) = 0
x = -3 or x = 1

check with Wolfram
http://www.wolframalpha.com/input/?i=Y%3Dx-2+%2C+Y%3Dx%5E2%2B3x-5

if x = -3, y = -3-2 = -5
if x = 1 , y = 1-2 = -1

x=-3, y=-5 ---> point (-3,-5)
x = 1 , y = -1 --->point (1, -1)