Asked by Adenaike Imoleayo
Solve the simultaneous equation and written in base two
11x+10y=1000
10x-y=10
11x+10y=1000
10x-y=10
Answers
Answered by
mathhelper
change to base 10
11x + 10y = 1000 ----> 3x + 2y = 8
10x - y = 10 -----------> 2x - y = 2
double the second: 4x - 2y = 4
add to the first:
7x = 12/7
x = 12/7
y = 10/7 , in base 10
back to base 2
10(base10) = 1010
12(base10) = 1100
7(base10) = 111
so x = 1100/111
y = 1010/111
or, you could set up an addition and a multiplication table in base 2 and do the
arithmetic in base 2 directly
11x + 10y = 1000 , now multiply the 2nd by 10
100x - 10y = 100
add them
111x = 1100
x = 1100/111 , etc, same answer as above
11x + 10y = 1000 ----> 3x + 2y = 8
10x - y = 10 -----------> 2x - y = 2
double the second: 4x - 2y = 4
add to the first:
7x = 12/7
x = 12/7
y = 10/7 , in base 10
back to base 2
10(base10) = 1010
12(base10) = 1100
7(base10) = 111
so x = 1100/111
y = 1010/111
or, you could set up an addition and a multiplication table in base 2 and do the
arithmetic in base 2 directly
11x + 10y = 1000 , now multiply the 2nd by 10
100x - 10y = 100
add them
111x = 1100
x = 1100/111 , etc, same answer as above
Answered by
oobleck
since y = 10x-10, use that to get
11x+10(10x-10) = 1000
11x + 100x - 100 = 1000
111x = 1100
x = 1100/111
y = 10x-10 = 11000/111 - 1110/111 = 1010/111
11x+10(10x-10) = 1000
11x + 100x - 100 = 1000
111x = 1100
x = 1100/111
y = 10x-10 = 11000/111 - 1110/111 = 1010/111
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