Question
simultaneous equation: 4x-9y^2=19, 2x+3y=11
Answers
oobleck
since 2x = 11-3y, 4x = 22-6y. So,
22-6y - 9y^2 = 19
9y^2 + 6y - 3 = 0
3(3y-1)(y+1) = 0
Now you know two values of y, and each will provide a value for x.
The line intersects the parabola at two points.
22-6y - 9y^2 = 19
9y^2 + 6y - 3 = 0
3(3y-1)(y+1) = 0
Now you know two values of y, and each will provide a value for x.
The line intersects the parabola at two points.
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