Asked by Nicole
Solve the simultaneous equation
1/p minus 1/q = 3/2
1/p plus 1/q = 4
1/p minus 1/q = 3/2
1/p plus 1/q = 4
Answers
Answered by
MathMate
Sum and difference problems are solved as follows:
Larger number = (sum+difference)/2
Smaller number = (sum-difference)/2
So
1/p = (4+3/2)/2 = 11/4
p = 1/(11/4) = 4/11
I will leave it to you to do the smaller number (1/q).
Larger number = (sum+difference)/2
Smaller number = (sum-difference)/2
So
1/p = (4+3/2)/2 = 11/4
p = 1/(11/4) = 4/11
I will leave it to you to do the smaller number (1/q).
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