You always want to set things equal to zero:
6x^2-13x+6 = 0
Now, just have to have some practice factoring to get to
(3x-2)(2x-3) = 0
Now, since if the product of two numbers is zero, one of the numbers must be zero. So, either
3x-2 = 0 and x = 2/3
or
2x-3 = 0 and x = 3/2
You can always use the quadratic formula, as well, even if it does not factor at all.
Solving By Factoring
6x^2-13x=-6
(x-8)(x-5)=x
4x(x-6)-x(x-2)=-24
Please show work I want to learn!!!!!!
3 answers
6 x^2 - 13 x + 6 = 0
we want 6 * 2 and a 1 to get 13
or 9 and 4
(3 x - 2)( 2x - 3 ) ah, 9 and 4
x = 2/3 or 3/2
we want 6 * 2 and a 1 to get 13
or 9 and 4
(3 x - 2)( 2x - 3 ) ah, 9 and 4
x = 2/3 or 3/2
4x(x-6)-x(x-2)=-24
4 x^2 - 24 x - x^2 + 2 x + 24 = 0
3 x^2 -22 x + 24 = 0
18 and 4 I bet
(3x - 4)(x - 6) ??? yes
x = 4/3 or 6
4 x^2 - 24 x - x^2 + 2 x + 24 = 0
3 x^2 -22 x + 24 = 0
18 and 4 I bet
(3x - 4)(x - 6) ??? yes
x = 4/3 or 6
2 answers