(2x-1)^2 = x^2 + 33
4x^2-4x+1 = x^2+33
3x^2-4x-32 = 0
(3x+8)(x-4) = 0
...
Solving By Factoring:
The length of the side of a large square is 1 cm less than twice the length of the of the side of a smaller square. The area of the large square is 33cm^2 more than the area of the small square. Find the length of the sides of the two squares.
Please show work!!!
1 answer
1 answer