Question

Solving By Factoring
6x^2-13x=-6

(x-8)(x-5)=x

4x(x-6)-x(x-2)=-24

Please show work I want to learn!!!!!!

Answer 1

You always want to set things equal to zero:

6x^2-13x+6 = 0

Now, just have to have some practice factoring to get to

(3x-2)(2x-3) = 0

Now, since if the product of two numbers is zero, one of the numbers must be zero. So, either

3x-2 = 0 and x = 2/3

or

2x-3 = 0 and x = 3/2

You can always use the quadratic formula, as well, even if it does not factor at all.

Answer 2

6 x^2 - 13 x + 6 = 0

we want 6 * 2 and a 1 to get 13
or 9 and 4

(3 x - 2)( 2x - 3 ) ah, 9 and 4

x = 2/3 or 3/2

Answer 3

4x(x-6)-x(x-2)=-24

4 x^2 - 24 x - x^2 + 2 x + 24 = 0

3 x^2 -22 x + 24 = 0

18 and 4 I bet

(3x - 4)(x - 6) ??? yes

x = 4/3 or 6