Asked by Giovanni
                I am looking factoring with the distributive property.
4m^2 + 4mp + 3mp + 3p^2
            
            
        4m^2 + 4mp + 3mp + 3p^2
Answers
                    Answered by
            John
            
    You have a few options...
If you group the terms then you will have a common factor at the end.
(4m^2 + 4mp)+ (3mp + 3p^2)
This should get you started : )
    
If you group the terms then you will have a common factor at the end.
(4m^2 + 4mp)+ (3mp + 3p^2)
This should get you started : )
                    Answered by
            John
            
    Or... just put your 4mp and 3mp together and factor the trinomial : )
4m^2 + 7mp + 3p^2
    
4m^2 + 7mp + 3p^2
                    Answered by
            Damon
            
    I  guess using distributive property backwards :)
4m (m+p)
+
3p (m+p)
=(4m+3p)(m+p)
    
4m (m+p)
+
3p (m+p)
=(4m+3p)(m+p)
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