salary study conducted. mean for men = $42,000. Std deviation = $9,000. mean for women = $39,000. Std dev for women = 8,000. If 100 men surveyed, at a CI of 95% what is the the most number of women surveyed if there was no Statistical difference in the mean for men and women?

Answer 1

use the formula

42-39)/(8/root100)

work out z value

then 1 -95% = 5% 0.05 on table which is 1.6445