just use your Z table.
(a)
60000 is -.8σ
75000 is +1.2σ
P(Z < -.8) = .2119
P(Z < 1.2) = .8849
So, P(-.8 < Z < 1.2) = .6730
Do the others in like wise.
According to Advertising Age, the average base salary for women working as copywriters is $66,000. Assume that the salaries are normally distributed and that the standard deviation is $7,500.
a. What is the probability of a woman receiving a salary between $60,000 and $75,000?
b. What is the probability of a woman receiving a salary of less than $60,000?
c. What is the probability of a woman receiving salary of more than 80,000?
d. What is the probability of a woman receiving a salary between $75,000 and $80,000?
e. How much (or more) would a woman have to make to have the salary in the top (upper) 3%?
1 answer