In a closed system, three objects have the following momentums: 110 kg⋅m/s

Question

110

kg
⋅
m/s
, −65 kg⋅m/s
−
65

kg
⋅
m/s
, and −100 kg⋅m/s
−
100

kg
⋅
m/s
. The objects collide and move together. What is the total momentum after the collision?(1 point)
Responses

55 kg⋅m/s
55

kg
⋅
m/s
55 kilograms times meters per second

−55 kg⋅m/s
−
55

kg
⋅
m/s
negative 55 kilograms times meters per second

−275 kg⋅m/s
−
275

kg
⋅
m/s
negative 275 kilograms times meters per second

275 kg⋅m/s

Answer 1

To find the total momentum after the collision, we need to sum the momenta of the three objects before the collision.

1. The momenta of the three objects are:

   • Object 1: \(110 , \text{kg} \cdot \text{m/s}\)
   • Object 2: \(-65 , \text{kg} \cdot \text{m/s}\)
   • Object 3: \(-100 , \text{kg} \cdot \text{m/s}\)

2. Now, we will add these momenta together: \[ \text{Total momentum} = 110 + (-65) + (-100) \] \[ = 110 - 65 - 100 \] \[ = 110 - 165 \] \[ = -55 , \text{kg} \cdot \text{m/s} \]

The total momentum after the collision is \(-55 , \text{kg} \cdot \text{m/s}\).

Therefore, the correct response is: −55 kg⋅m/s.