Question

In a closed system, three objects have the following momentums: 110 kg⋅m/s
110

kg
⋅
m/s
, −65 kg⋅m/s
−
65

kg
⋅
m/s
, and −100 kg⋅m/s
−
100

kg
⋅
m/s
. The objects collide and move together. What is the total momentum after the collision?(1 point)
Responses

−275 kg⋅m/s
−
275

kg
⋅
m/s
negative 275 kilograms times meters per second

55 kg⋅m/s
55

kg
⋅
m/s
55 kilograms times meters per second

275 kg⋅m/s
275

kg
⋅
m/s
275 kilograms times meters per second

−55 kg⋅m/s

Answer 1

To find the total momentum of the system after the collision, we need to sum the momenta of the three objects before the collision:

1. First object's momentum: \( 110 \, \text{kg} \cdot \text{m/s} \)
2. Second object's momentum: \( -65 \, \text{kg} \cdot \text{m/s} \)
3. Third object's momentum: \( -100 \, \text{kg} \cdot \text{m/s} \)

Now, we will sum these values:

\[
\text{Total momentum} = 110 \, \text{kg} \cdot \text{m/s} + (-65 \, \text{kg} \cdot \text{m/s}) + (-100 \, \text{kg} \cdot \text{m/s})
\]

Calculating this step-by-step:

\[
= 110 - 65 - 100
\]
\[
= 110 - 165
\]
\[
= -55 \, \text{kg} \cdot \text{m/s}
\]

Therefore, the total momentum after the collision is **−55 kg⋅m/s**.