Asked by Mzurist
A closed organ pipe (closed at one end) has a length of 8.67 x 10^-1 m.
(a) What is the fundamental frequency of this pipe?
(b) What is the frequency of the first overtone of this pipe?
(c) What is the frequency of the second overtone of this pipe?
(a) What is the fundamental frequency of this pipe?
(b) What is the frequency of the first overtone of this pipe?
(c) What is the frequency of the second overtone of this pipe?
Answers
Answered by
bobpursley
closed: lambda/2=8.67e-1
then f=speed sound/lambad
the fundamental wavelength λ1 = 2L . The first overtone adds one node as here, where the vibrating length is one wavelength. Thus, the wavelength here is: λ2 = L . The second overtone (third harmonic) has one further node: Thus, λ3 = 2/3 L.
then f=speed sound/lambad
the fundamental wavelength λ1 = 2L . The first overtone adds one node as here, where the vibrating length is one wavelength. Thus, the wavelength here is: λ2 = L . The second overtone (third harmonic) has one further node: Thus, λ3 = 2/3 L.
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