im guessing you meant sin(x)^5. in which case yeah you did it wrong. you derive (x)^k , k being a constant, like this k*(x)^(k-1)*x'
so f'(x)=5sin(x)^4*cos(x)
If f(x)=sin^5x, Find f'(x)
i don't know im doing right way
f'(x)= 5cosx * sin(x)
3 answers
Assuming that you mean [sinx]^5, the derivative is
5(sinx)^4 * cosx
I used the
"function of a function" rule for derivatives
I agree with Bryant
5(sinx)^4 * cosx
I used the
"function of a function" rule for derivatives
I agree with Bryant
my worksheet say sin^5 x. well thanks