If f(x)=sin^5x, Find f'(x)

Question

i don't know im doing right way
f'(x)= 5cosx * sin(x)

Answer 1

im guessing you meant sin(x)^5. in which case yeah you did it wrong. you derive (x)^k , k being a constant, like this k*(x)^(k-1)*x'
so f'(x)=5sin(x)^4*cos(x)

Answer 2

Assuming that you mean [sinx]^5, the derivative is
5(sinx)^4 * cosx

I used the
"function of a function" rule for derivatives

I agree with Bryant

Answer 3

my worksheet say sin^5 x. well thanks