Compute inverse functions to four significant digits.
cos^2x=3-5cosx
rewrite it as..
cos^2x + 5cosx -3=0
now you have a quadratic, solve for cos x using the equation
cosx=(-5 -+ sqrt (25 +12)/2
cos^2x=3-5cosx
rewrite it as..
cos^2x + 5cosx -3=0
now you have a quadratic, solve for cos x using the equation
cosx=(-5 -+ sqrt (25 +12)/2