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Can someone help me solve this problem:
cos^2x + 5cosx - 2= 0
I don't know how to find x
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Compute inverse functions to four significant digits.
cos^2x=3-5cosx rewrite it as.. cos^2x + 5cosx -3=0 now you have a
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Can someone help me solve this problem:
cos^2x + 5cosx - 2= 0 I am having trouble finding x
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Can someone help me solve this problem:
cos^2x + 5cosx - 2= 0 I am having some trouble finding x
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Compute inverse functions to four significant digits.
cos^2x=3-5cosx cos^2x + 5cosx -3=0 now you have a quadratic, solve for cos
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