If an object is projected upward with an initial velocity of 123 ft per​ sec, its height h after t seconds is h equals negative 16 t squared plus 123 t. Find the height of the object after 2 seconds.

1 answer

To find the height of the object after 2 seconds, we can use the given height equation:

\[ h(t) = -16t^2 + 123t \]

We need to substitute \( t = 2 \) into the equation:

\[ h(2) = -16(2)^2 + 123(2) \]

Calculating the squared term first:

\[ (2)^2 = 4 \]

Now substitute that back into the equation:

\[ h(2) = -16(4) + 123(2) \]

Now compute each part:

\[ h(2) = -64 + 246 \]

Now, add the two results:

\[ h(2) = 182 \]

Therefore, the height of the object after 2 seconds is 182 feet.