Asked by Retta
If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation hequals
minus16t squaredplusvtpluss,
where h is in feet. If the object is propelled from a height of 12
feet with an initial velocity of 96
feet per second, its height h is given by the equation hequals
minus16t squaredplus96tplus12
.
After how many seconds is the height 120
feet?
The time is nothing
seconds.
minus16t squaredplusvtpluss,
where h is in feet. If the object is propelled from a height of 12
feet with an initial velocity of 96
feet per second, its height h is given by the equation hequals
minus16t squaredplus96tplus12
.
After how many seconds is the height 120
feet?
The time is nothing
seconds.
Answers
Answered by
Scott
120 = -16 t^2 + 96 t + 12
0 = -4 t^2 + 24 t - 27
use quadratic formula to find t
0 = -4 t^2 + 24 t - 27
use quadratic formula to find t
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.