Question

If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t seconds is given by the equation hequals
minus16t squaredplusvtplus​s,
where h is in feet. If the object is propelled from a height of 12

feet with an initial velocity of 96

feet per​ second, its height h is given by the equation hequals
minus16t squaredplus96tplus12
.
After how many seconds is the height 120

​feet?
The time is nothing

seconds.

Answer 1

120 = -16 t^2 + 96 t + 12

0 = -4 t^2 + 24 t - 27

use quadratic formula to find t