Question
A 6.3 kg object is thrown upward with an acceleration of 0.45 m/s^2 . What is the magnitude of the force applied to the object?
Answers
g is added to the given acceleration
f = m a ... f = 6.3 kg * (9.81 + 0.45) = ? N
f = m a ... f = 6.3 kg * (9.81 + 0.45) = ? N
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