Asked by a.a

A ball is thrown directly upward at 19.6 m/s how much time passes before the ball reaches the top of its motion
Answered by That's Mr. Idontknowhwhatimdoing to you sir!
We know that at the top of the motion the velocity of the ball is 0.
Therefore 0 = v + at
0 = 19.6 + (-9.8)t
t = 19.6/9.8
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