Asked by a.a
A ball is thrown directly upward at 19.6 m/s how much time passes before the ball reaches the top of its motion
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That's Mr. Idontknowhwhatimdoing to you sir!
We know that at the top of the motion the velocity of the ball is 0.
Therefore 0 = v + at
0 = 19.6 + (-9.8)t
t = 19.6/9.8
Therefore 0 = v + at
0 = 19.6 + (-9.8)t
t = 19.6/9.8
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