Asked by Anonymous

A ball is thrown directly upward from an initial height of 200 feet with an initial velocity of 96 feet per second. After t seconds, the height of the ball above the ground is s(t) = 16t2+ 96t + 200.
a. After how many seconds will the ball reach its maximum height?
b. What was the maximum height?
c. How long will it take before the ball reaches the ground?

Answers

Answered by Reiny
see this similar question

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