Question
A ball is thrown directly upward from ground level with an initial velocity v(0) = 96 ft=s.
Assuming that the ball’s only acceleration is that due to gravity (i.e., a(t) = ��32 ft=s2),
determine the maximum height reached by the ball and the time it takes to return to ground
level.
Assuming that the ball’s only acceleration is that due to gravity (i.e., a(t) = ��32 ft=s2),
determine the maximum height reached by the ball and the time it takes to return to ground
level.
Answers
bobpursley
This is calculus?
height= vo*time-32*t^2
dheight/dt= vo-64t
t= 96/64 seconds.
max height then is the height(96/64). Calculate.
height= vo*time-32*t^2
dheight/dt= vo-64t
t= 96/64 seconds.
max height then is the height(96/64). Calculate.