Asked by fcv
A ball is thrown directly upward from ground level with an initial velocity v(0) = 96 ft=s.
Assuming that the ball’s only acceleration is that due to gravity (i.e., a(t) = ��32 ft=s2),
determine the maximum height reached by the ball and the time it takes to return to ground
level.
Assuming that the ball’s only acceleration is that due to gravity (i.e., a(t) = ��32 ft=s2),
determine the maximum height reached by the ball and the time it takes to return to ground
level.
Answers
Answered by
bobpursley
This is calculus?
height= vo*time-32*t^2
dheight/dt= vo-64t
t= 96/64 seconds.
max height then is the height(96/64). Calculate.
height= vo*time-32*t^2
dheight/dt= vo-64t
t= 96/64 seconds.
max height then is the height(96/64). Calculate.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.