The rock rises up to a height H where the velocity is zero, at which point the increase in potential energy M g H equals the initial kinetic energy, (1/2) M V^2
Therefore H = V^2/(2g) = 4.7 m
Since that is the answer you got, you must already know how to do the problem.
Don't forget to show the dimension (meters in this case). In physics and engineering, a number without a dimension should be marked wrong.
A rock is thrown straight upward with an initial velocity of 9.6 m/s in a location where the acceleration due to gravity has a magnitude of 9.81 m/s^2. To what height does it rise?
i got 4.7
can you please show me how to solve for this last one
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