Asked by Aisumi

A rock is thrown straight upward with an initial velocity of 9.6 m/s in a location where the acceleration due to gravity has a magnitude of 9.81 m/s2. To what height does it rise? Help meh please.

Answered by Aisumi
d = v^2/(2a)

d = 9.6^2/(2(9.81))

d = 4.7 m haha i answered it myself
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