Asked by angela
A ball is thrown straight upward from ground level with a velocity of 41 m/s How much time passes before the ball strikes the ground? Disregard air resistance.
Answers
Answered by
Jai
Use the formula:
h = vo*t - (1/2)gt^2
We know that
vo = 41
g = 9.8
h = 0 (since it strikes the ground)
0 = 41t - (1/2)(9.8)t^2
Solve for t. One of the answers is t = 0, but this is the time before the release of the ball. Get the other value of t.
h = vo*t - (1/2)gt^2
We know that
vo = 41
g = 9.8
h = 0 (since it strikes the ground)
0 = 41t - (1/2)(9.8)t^2
Solve for t. One of the answers is t = 0, but this is the time before the release of the ball. Get the other value of t.
Answered by
Anonymous
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