Question

A ball is thrown straight upward from ground level with a velocity of 41 m/s How much time passes before the ball strikes the ground? Disregard air resistance.

Answers

Jai
Use the formula:
h = vo*t - (1/2)gt^2
We know that
vo = 41
g = 9.8
h = 0 (since it strikes the ground)

0 = 41t - (1/2)(9.8)t^2

Solve for t. One of the answers is t = 0, but this is the time before the release of the ball. Get the other value of t.
Anonymous
dum ansswer never ever get any thing right dum dum fat rat

Related Questions