Asked by glenda
if an object is projected upward from ground level with an initial velocity of 64 ft per sec,its height h in feet t seconds later is h=-16t+64t.after how many seconds is the height 48 ft.
Answers
Answered by
bobpursley
48= -16t+64t^2
put it in quadratic form:
4t^2-t-3=0
(2t-3)(2t+1)=0
so t= 3/2 second, disregard the negative answer
put it in quadratic form:
4t^2-t-3=0
(2t-3)(2t+1)=0
so t= 3/2 second, disregard the negative answer
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