If 488 mL of 2.9 molar HCl solution is added to

191 mL of 2.8 molar Ba(OH)2 solution, what
will be the molarity of BaCl2 in the resulting
solution?
Answer in units of M.

1 answer

I answered a question quite similar to this a couple of days ago. There is no BaCl2 in solution. There are Ba ions and chloride ions and there are more chloride ions than barium ions. But to try to calculate a M of an ionic compound in which the positive barium ions and the negative chloride ions are not equal is nonsense.