If 400 mL of 3.2 molar HCl solution is added to 300 mL of 2 molar NaOH solution, what will be the molarity of NaCl in the resulting solution? Answer in units of M

Answer 1

HCl + NaOH ==> NaCl + H2O
mols HCl = M x L = 3.2 x 0.4 = 1.28
mols NaOH = M x L = 2 x 0.3 = 0.6

mols NaCl formed = 0.6
M NaCl = mols/L = 0.6/(0.4+0.3) = ?

Answer 2

HCL + NAOH -> NaCL + H2)
Mols HCL = M x L = 3.2 x 0.4 = 1.28
Mols NaOH = M x L = 2 x 0.3 = 0.6

mols NaCl formed = 1.28
M NaCl = mols/L = 1.28/(.4 + .3) = 1.829