If 400 mL of 3.5 molar HCl solution is added to 200 mL of 2.3 molar NaOH solution, what will be the molarity of NaCl in the resulting solution? Answer in units of M.

Answer 1

This is a limiting reagent.
HCl + NaOH ==> NaaCl + H2O

mols HCl = M x L = ? = approx 1.4
mols NaOH = M x L = ? = approx 0.46
So the amount of NaCl formed is 0.46 mols. The volume is 400 + 200 = 600 mL = 0.6 L
M = mols/L