If 300 mL of 3.9 molar HCl solution is added

Question

to 200 mL of 2.2 molar NaOH solution, what
will be the molarity of NaCl in the resulting
solution?
Answer in units of M

Answer 1

Since HCl and NaOH react in a 1:1 ratio, 0.200 L x 2.2 M NaOH = 0.440 mols will react with 0.200 x 3.9 = 1.17 mols HCl to form (ONLY) 0.44 mol NaCl.
M = mols/L soln (careful--the solution volume will be 300 + 200 = 500 mL or 0.5L).

Answer 2

656+56+