projectile hits the ground when s(t) = 0 meaning the height off the ground is zero.
0 = 144t -16 t^2
Factor out the t:
0 = t(144 -16t)
set each part = to zero
t = 0 the projectile wasn't launched yet
and 144- 16t = 0
solve for t to find out how long the projectile was in the air before hitting the ground.
Height of a Projectile.
The height of a projectile is described by the equation:
s(t)=144t-16t^(2)
Where t is in seconds and s(t) is the height of the projectile at time t. Find when the projectile hits the ground.
1 answer