Height of a Projectile.

The height of a projectile is described by the equation:

s(t)=144t-16t^(2)

Where t is in seconds and s(t) is the height of the projectile at time t. Find when the projectile hits the ground.

1 answer

projectile hits the ground when s(t) = 0 meaning the height off the ground is zero.

0 = 144t -16 t^2

Factor out the t:
0 = t(144 -16t)

set each part = to zero

t = 0 the projectile wasn't launched yet

and 144- 16t = 0
solve for t to find out how long the projectile was in the air before hitting the ground.