Asked by colin

The height, h(t), of a projectile, in metres, can be modelled by the equation
h(t) = 14t – 5t2, where t is the time in seconds after the projectile is released. Can the projectile ever reach a height of 9m? Explain.

Answers

Answered by Steve
h(t) = t(14-5t)

max height is achieved at t = 7/5
h(7/5) = 9.8

so, yes.
Answered by Ararsa
h(t)=-16t³+100t
Answered by Brhane
2&√13 -2÷2
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