Given three capacitors 0.3uF, 0.5 uF and 0.2 uF, the joint capacitance when arranged to give minimum capacitance is?

Answer 1

in parallel, they just add up
in series, the resultant capacitance x is found by using
1/x = 1/.3 + 1/.5 + 1/.2
x = 0.097 uF