Asked by Xander
Two identical capacitors are hooked in series to a 16.6 V emf. If the charge stored on any one of the capacitors is 0.88 micro-Coulombs after the capacitors are fully charged, what is the capacitance of either one of the capacitors?
Answers
Answered by
Damon
The charge on each is the same.
The voltage on each is half the battery = 8.3 volts
C = q/V
C = .88 *10^-6 /8.3
The voltage on each is half the battery = 8.3 volts
C = q/V
C = .88 *10^-6 /8.3
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