To obtain the maximum capacitance, we should connect the capacitors in parallel. When capacitors are connected in parallel, the total capacitance \( C_{total} \) is the sum of the individual capacitances:
\[ C_{total} = C_1 + C_2 + C_3 \]
Given the capacitances:
- \( C_1 = 4F \)
- \( C_2 = 3F \)
- \( C_3 = 2F \)
Now, we can calculate the total capacitance:
\[ C_{total} = 4F + 3F + 2F = 9F \]
Thus, the maximum capacitance that can be obtained by connecting the three capacitors is 9 Farads.
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