To arrange the capacitors to give minimum capacitance, they should be connected in parallel. The formula for calculating the total capacitance when capacitors are connected in parallel is:
C_total = C1 + C2 + C3
Plugging in the values given:
C_total = 0.3uF + 0.5uF + 0.2uF
C_total = 1.0uF
Therefore, the joint capacitance when arranged to give minimum capacitance is 1.0uF.
Answer: B. 1.0uF
en three capacitors 0.3uF, 0.5 uF and 0.2 uF,
the joint capacitance when arranged to give
minimum capacitance is
A. 0.3uF
B. 1.0uF
C. 0.1uF
D. 0.5uF
1 answer