en three capacitors 0.3uF, 0.5 uF and 0.2 uF,

the joint capacitance when arranged to give
minimum capacitance is
A. 0.3uF
B. 1.0uF
C. 0.1uF
D. 0.5uF

1 answer

To arrange the capacitors to give minimum capacitance, they should be connected in parallel. The formula for calculating the total capacitance when capacitors are connected in parallel is:

C_total = C1 + C2 + C3

Plugging in the values given:

C_total = 0.3uF + 0.5uF + 0.2uF
C_total = 1.0uF

Therefore, the joint capacitance when arranged to give minimum capacitance is 1.0uF.

Answer: B. 1.0uF