y = ax + b
m = 3/4
y = 3/4 x + b
You need to find b for this equation.
Substitute one of the given points into your equation and solve for b.
Then use that b value for your equation.
Find the equation of the line.
find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-8, -6) and (x2, y2) = (0, 0)
slope 0-(-6)/0-(-8)= 3/4
how would I write it?
y=3/4x or y=3/4x+0 ?
4 answers
I don't get a value for b, What am I missing?
You were given the points,
(x1, y1) = (-8, -6) and (x2, y2) = (0, 0)
y = 3/4 x + b
Use one of the given points, for example,
(-8, -6)
Solve for b
-6 = 3/4(-8) + b
b = 0
Therefore, the equation is
y = 3/4 x + 0
y = 3/4 x
I guess I miss-understood you. I didn't realize that you had already found the b value to be zero. (Since you didn't state that b = 0 originally). I shouldn't have assumed.
(x1, y1) = (-8, -6) and (x2, y2) = (0, 0)
y = 3/4 x + b
Use one of the given points, for example,
(-8, -6)
Solve for b
-6 = 3/4(-8) + b
b = 0
Therefore, the equation is
y = 3/4 x + 0
y = 3/4 x
I guess I miss-understood you. I didn't realize that you had already found the b value to be zero. (Since you didn't state that b = 0 originally). I shouldn't have assumed.
Ok thanks