Question

Find the equation of the line that goes through (3,-4) with slope m=-1/4

Answer 1

y - y1 = m(x-x1)
y - (-4) = -1/4(x -3)

y + 4 = -1/4 x + 3/4

y = -1/4 x + 3/4 -16/4

y = -1/4 x - 13/4
This is in y = mx + b form

in ax + by = c form

4y = -x -13
x + 4y = -13

You could also find the equation by just using

y = mx + b

-4 = -1/4 (3) + b

-4 = -3/4 + b
-16/4 + 3/4 = b
-13/4 = b

so y - -1/4 x - 13/4