Asked by help please
Find the equation of a line that is perpendicular to y=2x+7, and passes through the point (-4, 7)
I got the answer y=-1/2x+5, is that the correct equation??
I got the answer y=-1/2x+5, is that the correct equation??
Answers
Answered by
Scott
got the right slope
point-slope ... y - 7 = -1/2 (x + 4)
equation looks good
point-slope ... y - 7 = -1/2 (x + 4)
equation looks good
Answered by
help please
so scott my equation is right
Answered by
Reiny
easiest way:
Since the slopes must be negative reciprocals of each other, the new equation must look like this
y = (-1/2)x + b
plug in your point (-4,7)
7 = (-1/2)(-4) + b
5 = b
y = (-1/2)x + 5
Since the slopes must be negative reciprocals of each other, the new equation must look like this
y = (-1/2)x + b
plug in your point (-4,7)
7 = (-1/2)(-4) + b
5 = b
y = (-1/2)x + 5
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