Asked by joy
Find an equation of the line (in slope-intercept form) that passes through the point (7,5) and is perpendicular to the line 7x + 10y - 17 = 0
y=?
y=?
Answers
Answered by
Zac
First put the perpendicular line equation into y=mx+b form. Your first step should be to subtract the 10y from both sides.
Then using the y = mx + b equation, you know the slope of the parallel line. Your line is perpendicular to the m value in the new equation. To find the slope use: -1/m. That number will be your m value in your equation.
Finally plug your numbers into the basic starter equation:
y-(yval)=m(x-(xval))
your yval and xval numbers are from the point the line passes through
Then using the y = mx + b equation, you know the slope of the parallel line. Your line is perpendicular to the m value in the new equation. To find the slope use: -1/m. That number will be your m value in your equation.
Finally plug your numbers into the basic starter equation:
y-(yval)=m(x-(xval))
your yval and xval numbers are from the point the line passes through
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