look at it this way...
f(x) = (x^2 – 16)^2
= (x^2 - 16)(x^# - 16)
= (x+4)(x-4)(x+4)(x-4)
the answer should be obvious, trust yourself !
Find all of the zeros of the polynomial function and state the multiplicity of each.
f (x) = (x^2 – 16)^2
A. – 4 with multiplicity 2 and 4 with multiplicity 2
B. – 4i with multiplicity 2 and 4i with multiplicity 2
C. 4 with multiplicity 2
D. 4 with multiplicity 4
I think the answer is A, any thoughts?
4 answers
I wasn't sure but it is A then?
yes,
how about that confidence thing ?
how about that confidence thing ?
Not too good with math, actually i am no good at it.