f(x) = (x2-16)2
= ((x+4)(x-4))2
= (x+4)2(x-4)2
Can you take it from here?
Find all of the zeros of the polynomial function and state the multiplicity of each.
f (x) = (x^2 – 16)^2
A. – 4 with multiplicity 2 and 4 with multiplicity 2
B. – 4i with multiplicity 2 and 4i with multiplicity 2
C. 4 with multiplicity 2
D. 4 with multiplicity 4
5 answers
Yes this is what I got, is it correct?
C. 4 with multiplicity 2 ?
C. 4 with multiplicity 2 ?
No, it is not the case. There are four roots for a quartic equation, so one single root with multiplicity of 2 does not suffice.
When you have the factor (x+4)2, that implies x=-4 with multiplicity of 2.
If you repeat the process with the factor (x-4)2, you will find the answer you need.
When you have the factor (x+4)2, that implies x=-4 with multiplicity of 2.
If you repeat the process with the factor (x-4)2, you will find the answer you need.
Wow I am confused now. So does the answer include the i? which is
B. – 4i with multiplicity 2 and 4i with multiplicity 2
OR
A. – 4 with multiplicity 2 and 4 with multiplicity 2
I am goin to say A but I could be wrong.
B. – 4i with multiplicity 2 and 4i with multiplicity 2
OR
A. – 4 with multiplicity 2 and 4 with multiplicity 2
I am goin to say A but I could be wrong.
A is correct. The roots are real, so there is no i involved.
There are two distinct roots, ±4 each with multiplicity of 2. So A is the answer.
There are two distinct roots, ±4 each with multiplicity of 2. So A is the answer.
3 answers