To find the zeros of the polynomial function \( f(x) = 5(x - 2)(x + 8)^2 \) and determine their multiplicities and behavior, follow these steps:
Step 1: Identify the Zeros
To find the zeros of the function, set \( f(x) = 0 \): \[ 5(x - 2)(x + 8)^2 = 0 \] This yields two factors to solve:
- \( x - 2 = 0 \) → \( x = 2 \)
- \( (x + 8)^2 = 0 \) → \( x + 8 = 0 \) → \( x = -8 \)
Step 2: Find the Multiplicities
- The zero \( x = 2 \) comes from the factor \( (x - 2) \) which has a multiplicity of 1 (since it's linear).
- The zero \( x = -8 \) comes from the factor \( (x + 8)^2 \) which has a multiplicity of 2 (since it's a quadratic).
Summary of Zeros and Multiplicities
- Zeros: \( 2 \) and \( -8 \)
- Multiplicity of \( x = 2 \): 1
- Multiplicity of \( x = -8 \): 2
Determining the Behavior of the Graph at Each Zero
- For a zero with odd multiplicity, the graph crosses the x-axis.
- For a zero with even multiplicity, the graph touches the x-axis and turns around.
At the Zeros:
- At \( x = 2 \): The multiplicity is 1 (odd), so the graph crosses the x-axis.
- At \( x = -8 \): The multiplicity is 2 (even), so the graph touches the x-axis and turns around.
Final Answers
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The zero(s) is/are:
- \( -8, 2 \)
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The multiplicity of the largest zero (\( x = 2 \)):
- \( 1 \)
-
The multiplicity of the other zero (\( x = -8 \)):
- \( 2 \)
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The graph touches the x-axis and turns around at:
- \( x = -8 \)
Selection Summary:
- Choose option A: There are two zeros. The multiplicity of the largest zero is 1, and the multiplicity of the other zero is 2.
- The function crosses the x-axis at \( x = 2 \) and touches the x-axis and turns around at \( x = -8 \).