Asked by Anonymous
                Figure 1 shows a simplication of the AM1.5 solar spectrum at 1000W/m2. The spectrum is divided in three spectral ranges:
A for 0nm<λ<620nm
B for 620nm<λ<1240nm
C for 1240nm<λ<1860nm
The photon flux in each spectral range is also shown in the figure.
a) The hydrogenated silicon carbide material (a-SiC:H) is a new type of amorphous semiconductor material which has been recently studied for PV applications. This material has a relative large band gap of 2.0 eV. Imagine we integrate this material in a single-junction p-i-n solar cell as shown in Figure 2a below. In which spectral ranges does this solar cell convert light into charge carriers?
1)A
2)B
3)C
b) What is the Jsc (in mA/cm2) of the solar cell if only 65% of the absorbed photons result in a current?
c) The Voc in V of the a-SiC:H solar cell can be roughly estimated by the equation:
Voc=Egap(J)2q=Egap(eV)2
where q is the elementary charge, Egap(J) is the bandgap energy expressed in Joules, and Egap(eV) is the bandgap energy expressed in eV. The fill factor of the solar cell is FF=0.80. What is the efficiency of the solar cell (in %) ?
An up-convertor is a material which can convert two low-energy photons into a higher energy photon. Placing an up-convertor in our solar cell can help to reduce the spectral mismatch, since it can convert some photons with energy lower than 2 eV, which are not absorbed by the a-SiC:H cell, into a photon with an energy higher than 2 eV. Figure 2b depicts this possibility.
d) In the up-convertor 1, two photons are converted into one photon with 100% conversion efficiency. If all photons with energy above that of the band gap of a-SiC:H are absorbed in the a-SiC:H layer, in which spectral range can the photons be up-converted so that they contribute to the current in the cell as well?
1)A
2)B
3)C
e) In that case what would be the short-circuit current density and the efficiency of the solar cell illustrated in Figure 2b? Assume again that 65% of the absorbed photons result in a current.
Short-circuit current density in mA/cm2
Efficiency in %
f) In up-convertor 2 (see Figure 2c), three photons are converted into one photon with 100% conversion efficiency. if all photons with energy above that of the band gap of a-SiC:H are absorbed in the p-i-n cell, and convertor 1 absorbs only the photons in the spectral range as considered in parts e) and f), in which spectral part can the photons be up-converted by convertor 2 so that they contribute to the current in the cell as well?
1)A
2)B
3)C
g) In that case what would be the short-circuit current density and the efficiency of the solar cell illustrated in Figure 2c? Assume that 65% of the absorbed photons result in a current.
Short-circuit current density in mA/cm2
Efficiency in %
            
        A for 0nm<λ<620nm
B for 620nm<λ<1240nm
C for 1240nm<λ<1860nm
The photon flux in each spectral range is also shown in the figure.
a) The hydrogenated silicon carbide material (a-SiC:H) is a new type of amorphous semiconductor material which has been recently studied for PV applications. This material has a relative large band gap of 2.0 eV. Imagine we integrate this material in a single-junction p-i-n solar cell as shown in Figure 2a below. In which spectral ranges does this solar cell convert light into charge carriers?
1)A
2)B
3)C
b) What is the Jsc (in mA/cm2) of the solar cell if only 65% of the absorbed photons result in a current?
c) The Voc in V of the a-SiC:H solar cell can be roughly estimated by the equation:
Voc=Egap(J)2q=Egap(eV)2
where q is the elementary charge, Egap(J) is the bandgap energy expressed in Joules, and Egap(eV) is the bandgap energy expressed in eV. The fill factor of the solar cell is FF=0.80. What is the efficiency of the solar cell (in %) ?
An up-convertor is a material which can convert two low-energy photons into a higher energy photon. Placing an up-convertor in our solar cell can help to reduce the spectral mismatch, since it can convert some photons with energy lower than 2 eV, which are not absorbed by the a-SiC:H cell, into a photon with an energy higher than 2 eV. Figure 2b depicts this possibility.
d) In the up-convertor 1, two photons are converted into one photon with 100% conversion efficiency. If all photons with energy above that of the band gap of a-SiC:H are absorbed in the a-SiC:H layer, in which spectral range can the photons be up-converted so that they contribute to the current in the cell as well?
1)A
2)B
3)C
e) In that case what would be the short-circuit current density and the efficiency of the solar cell illustrated in Figure 2b? Assume again that 65% of the absorbed photons result in a current.
Short-circuit current density in mA/cm2
Efficiency in %
f) In up-convertor 2 (see Figure 2c), three photons are converted into one photon with 100% conversion efficiency. if all photons with energy above that of the band gap of a-SiC:H are absorbed in the p-i-n cell, and convertor 1 absorbs only the photons in the spectral range as considered in parts e) and f), in which spectral part can the photons be up-converted by convertor 2 so that they contribute to the current in the cell as well?
1)A
2)B
3)C
g) In that case what would be the short-circuit current density and the efficiency of the solar cell illustrated in Figure 2c? Assume that 65% of the absorbed photons result in a current.
Short-circuit current density in mA/cm2
Efficiency in %
Answers
                    Answered by
            I.G.
            
    a) A
d) B
f) C
    
d) B
f) C
                    Answered by
            Anonymous
            
    Can you also give out the rest of the answers?? thanks
    
                    Answered by
            jen
            
    where is the rest of the answers?
    
                    Answered by
            Anonymous
            
    jen the answers are in your nose. 
Next time ask nicely.
    
Next time ask nicely.
                    Answered by
            Ken
            
    It is not possible to solve the rest of the answers the figure are missing.
 
    
                    Answered by
            Anonymous
            
    Please Is anybody who can help this question? Thanks
    
                    Answered by
            Ken
            
    Why don't you add the missing figures
2a, 2b, and 2c
    
2a, 2b, and 2c
                    Answered by
            A
            
    courses edx org/c4x/DelftX/ET3034TUx/asset/Week5_Specturm png
This is the image's url, replace the spaces with dots
    
This is the image's url, replace the spaces with dots
                    Answered by
            Ken
            
    Link doesn't works
    
                    Answered by
            A
            
    postimg org/image/kylqxalt7/
Try this put a dot after 'postimg'
    
Try this put a dot after 'postimg'
                    Answered by
            Anonymous
            
    The link is for fig. 1
still need fig 2a, 2b, and 2c
    
still need fig 2a, 2b, and 2c
                    Answered by
            Anonymous
            
    ϕ=9.3∗1020m−2s−1 for 300nm<λ<650nm
ϕ=8.4∗1020m−2s−1 for 650nm<λ<850nm
ϕ=1.4∗1021m−2s−1 for 850nm<λ<1250nm
    
ϕ=8.4∗1020m−2s−1 for 650nm<λ<850nm
ϕ=1.4∗1021m−2s−1 for 850nm<λ<1250nm
                    Answered by
            Anonymous
            
    AND
Voc = Egap(J)/2q = Egap(eV)/2
    
Voc = Egap(J)/2q = Egap(eV)/2
                    Answered by
            Anonymous
            
    Sorry the above 2 answers are for another question...
    
                    Answered by
            Anonymous
            
    use this link
postimg org/image/htap77x5d/
    
postimg org/image/htap77x5d/
                    Answered by
            Ken
            
    1a. = A
1.b = 10.4mA/cm2, 8.33%
1c = B
1d = 18mA/cm2, 14%
1f = C
1g = 18.7 mA/cm2, 15%
    
1.b = 10.4mA/cm2, 8.33%
1c = B
1d = 18mA/cm2, 14%
1f = C
1g = 18.7 mA/cm2, 15%
                    Answered by
            Anonymous
            
    Thanks
    
                    Answered by
            Anonymous
            
    Can you please answer this too
jiskha com/display.cgi?id=1382813246
    
jiskha com/display.cgi?id=1382813246
                    Answered by
            UNO
            
    Thanks Ken
    
                    Answered by
            Lauren
            
    what are the answer to the e) please 
    
                    Answered by
            Naif
            
    e 14 and thanks for the answers guys i will pray for u :)
    
                    Answered by
            student
            
    e is 14 and 14 again
    
                    Answered by
            MANIRAGUHA Eric
            
    1)A
2)10 mA/cm^2
3)8%
4)B
5)18mA/cm^2
6)14%
7)C
8)19mA/cm^2
9)15%
Enjoy guys!!!!
    
2)10 mA/cm^2
3)8%
4)B
5)18mA/cm^2
6)14%
7)C
8)19mA/cm^2
9)15%
Enjoy guys!!!!
                    Answered by
            SB
            
    When adding the photon flux of A and half of the photon flux of B I come to 1.55E+17 photons/cm2. This gives a short-circuit current density of 16.12mA/cm2 which is wrong. Where is my mistake???
    
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