MANIRAGUHA Eric

J0=1.95∗10−10mA/cm2=1.95*10^-9A/m^2 Jph=40mA/cm2=400A/m^2 Voc=kT/q*ln(Jph/J0+1) T=300K k=1.35*10^-23J/K q=1.6*10^-19C J(V)=Jph−J0(eqVkT−1) The open-circuit voltage is the voltage at which the net current is zero where J(Voc)=0 Solving for Voc we have Voc=...

0.659 V

1)81.63 2)65.31 3)15 4)12

78 and 13

Consider a c-Si solar cell whose fingers have a resistance R=0.1 Ohm. What would be the finger's resistance (in Ohm) if the finger's width is doubled and the finger's height is one third of its initial value?

I=200∗10−9∗1.5∗1092+1000∗10−9∗1.5∗1092=900W/m2

c)Because the voltage difference created in the photoelectrode is not able to produce enough voltage to drive the reaction c)1.43V

1)A 2)10 mA/cm^2 3)8% 4)B 5)18mA/cm^2 6)14% 7)C 8)19mA/cm^2 9)15% Enjoy guys!!!!

a)Tcell=40 oC b)Pout=270W

1)4 2)4

R=9.34

a)2400 b)50 c)60 d)90 e)90 f)81

4)Overall lifetime of the PV system