Evaluate the limit, if it exists.

lim (sqrt(x+2) -3)/(x-7)
(x -> 7)

I tried multiplying the numberator and denominator by the conjugate of the numberator (sqrt(x+2) +3) but, unless I multiplied wrong, I still ended up getting 0/0, when my calculator and the book say that I should get an answer of 1/6. Is this the wrong way to approach the problem?

2 answers

You multiplied wrong.

You should have gotten in the numberator

x+2-9= x-7, which divides out the x-7 in the denominator, leaveing (sqrt(x+2) + 3), or 1/6
Ah, ok. I multiplied the (x-7) out in the denominator and must have multiplied wrong. Thank you!
Similar Questions
  1. Evaluate the limit, if it exists.lim x->16 (4-sqrt(x))/(16x-x^2)
    1. answers icon 1 answer
  2. Determine whether on not the following limit exists. If, so compute the limit.lim x->3 of sqrtx - 4 / x^3 +27 sqrt 3 - 4 / x^3 +
    1. answers icon 2 answers
  3. Evaluate the definite integral.function: (t+8)(t^2+3) with respect to variable t lower limit: -sqrt(2) upper limit: sqrt(2)
    1. answers icon 2 answers
  4. Find the limit if it exists.The limit of (sqrt(x+1)-2)/(x-3) as x tends to 3. The limit of (sqrt(x+5)-sqrt(5))/x as x tends to 0
    1. answers icon 1 answer
more similar questions