Asked by Anya
Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.)
lim t^2-64/2t^2+17t+8
t→−8
Please show steps!
lim t^2-64/2t^2+17t+8
t→−8
Please show steps!
Answers
Answered by
Steve
the expression is (t-8)(t+8) / (2t+1)(t+8)
That is, for all t ≠ -8, it is just (t-8)/(2t+1)
I think you can handle that limit, eh?
wolframalpha is your friend ...
www.wolframalpha.com/input/?i=lim(t+-%3E+-8)+(+t%5E2-64)%2F(2t%5E2%2B17t%2B8)
That is, for all t ≠ -8, it is just (t-8)/(2t+1)
I think you can handle that limit, eh?
wolframalpha is your friend ...
www.wolframalpha.com/input/?i=lim(t+-%3E+-8)+(+t%5E2-64)%2F(2t%5E2%2B17t%2B8)
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