When x = 9
9 x − x ^ 2 = 9 * 9 - 9 ^ 2 = 81 - 81 = 0
and
3 - sqt( x ) / ( 9 x − x ^ 2 ) =
3 - sqt( 9 ) / ( 9 x − x ^ 2 ) =
3 - 3 / 0 =
3 - ( + OR - infinity )
So:
limit 3 − square root( x ) /(9 x − x ^ 2 ) as x ->9 =
+ OR - infinity
Evaluate the limit, if it exists.
lim , 3 − square root(x) /(9x − x^2)
x�¨9
1 answer